LearnChemE

Calculating Diameter in Pipe Flow: Screencast

BRIEF EXPLANATION OF THE SCREENCAST HERE.  IN THE IMAGE BELOW, REPLACE THE “src” ATTRIBUTE OF THE IFRAME TEXT WITH THE SCREENCAST LINK.  IF IT IS NOT AN INTERACTIVE SCREENCAST (E.G. A YOUTUBE VIDEO), THEN DELETE THE ELEMENT BELOW AND USE A “Video” ELEMENT.

Important Equations:

The value of the Reynold’s number, RE, determines the flow regime in a pipe.

\[Re = \frac{\rho VD}{\mu} = \frac{VD}{\nu}\]

where \(\rho\) = density of the fluid, \(V\) = average velocity, \(D\) = diameter of the pipe, \(\mu\) = dynamic viscosity, and \(\nu\) = kinematic viscosity.

The energy equation is the governing equation for viscous pipe flow.

\[\frac{p_1}{\gamma} + \frac{V^2_1}{2g} + z_1 = \frac{p_2}{\gamma} + \frac{V^2_2}{2g} + z_2 + h_L\]

where \(p\) = pressure, \(V\) = velocity, \(g\) = gravity, \(z\) = height measured from some origin, and \(h_L\) = head loss, which consists of:

\[h_{L,major} = f \frac{L}{D} \frac{V^2}{2g}\]

\[h_{L,minor} = \frac{\Sigma K_L V^2}{2g}\]

where \(f\) = friction factor and \(K_L\) = loss coefficient.

The Colebrook equation is a method to solve for the friction factor.

\[\frac{1}{\sqrt{f}} = -2.0 log \left( \frac{\frac{\epsilon}{D}}{3.7} + \frac{2.51}{Re \sqrt{f}} \right)\]

where \(\epsilon\) = surface roughness